Re: R: LOGO-L> permuted list

[Frank Caggiano <caggiano@atlantic.net>]

Hi,

There is a 'gotcha' in this one.  Try 'show compare [a a c] [a b c]' 

This happens because you are only removing the item from the first list.
See my response to this query.

regards



paspal wrote:
> 
> Hi,
> Here is my solution for permutated lists:
> 
> ;----------------------------------
> to comp :list1 :list2
> if emptyp :list1 [op "true]
> ifelse memberp (first :list1) :list2 ~
>     [op comp butfirst :list1 :list2] ~
>     [op "false]
> end
> 
> to compare :list1 :list2
> ifelse equalp (count :list1) (count :list2) ~
>    [op comp :list1 :list2] ~
>    [op "false]
> end
> ;------------------------------------
> try this:
> show compare [a b c] [b a c]
> and then
> show compar [a [b] c] [[b] a c]
> 
> Paspal
> paspal@mail.bielnet.it
> 
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-- 
Frank Caggiano
caggiano@atlantic.net
http://www.atlantic.net/~caggiano
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